Home
Class 10
MATHS
{:(3x + 2y = 4),(2x - 3y = 7):}...

`{:(3x + 2y = 4),(2x - 3y = 7):}`

Text Solution

Verified by Experts

The correct Answer is:
x = 2, y = - 1
Promotional Banner

Topper's Solved these Questions

  • LINEAR EQUATIONS IN TWO VARIABLES

    NAGEEN PRAKASHAN|Exercise Exercise 3c|15 Videos
  • LINEAR EQUATIONS IN TWO VARIABLES

    NAGEEN PRAKASHAN|Exercise Exercise 3d|35 Videos
  • LINEAR EQUATIONS IN TWO VARIABLES

    NAGEEN PRAKASHAN|Exercise Exercise 3a|18 Videos
  • INTRODUCTION TO TRIGONOMETRY

    NAGEEN PRAKASHAN|Exercise Revision Exercise Long Answer Questions|5 Videos
  • POLYNOMIALS

    NAGEEN PRAKASHAN|Exercise Revision Exercise Long Answer Questions|4 Videos

Similar Questions

Explore conceptually related problems

3x + 2y = 0, x + 3y = 7

Find the values of (x-y) , if (i) 3x + 4y = 11 , 4x + 3y = 10 (ii) 3x + 2y = 8 , 2x + 3y = 7

3x - [4y - {7x - (3z - 2y) + 4z - 3(x + 3y - 2z)}]

{:(2x + 3y = 7),((a - 1)x +(a +2)y = 3a):}

3x+2y=5 2x-3y=7

Solve for x and y, using substitution method : 2x + y = 7, 4x - 3y + 1 =0

Simplify: (2x + 5y)(3x + 4y) - (7x + 3y)(2x + y)

The equaiton of the lines representing the sides of a triangle are 3x - 4y =0 , x+y=0 and 2x - 3y = 7 . The line 3x + 2y = 0 always passes through the

7 (y + 3) -2 (x + 2) = 14.4 (y-2) +3 (x-3) = 2

The equation of straight line belonging to both the families of lines (x-y+1)+lambda_1(2x-y-2)=0 and (5x+3y-2)+lambda_2(3x-y-4)=0 where lambda_1, lambda_2 are arbitrary numbers is (A) 5x -2y -7=0 (B) 2x+ 5y - 7= 0 (C) 5x + 2y -7 =0 (D) 2x- 5y- 7= 0