Home
Class 10
MATHS
{:(y = 2x - 6),(y = 0):}...

`{:(y = 2x - 6),(y = 0):}`

Text Solution

Verified by Experts

The correct Answer is:
x = 3, y = 0
Promotional Banner

Topper's Solved these Questions

  • LINEAR EQUATIONS IN TWO VARIABLES

    NAGEEN PRAKASHAN|Exercise Exercise 3c|15 Videos
  • LINEAR EQUATIONS IN TWO VARIABLES

    NAGEEN PRAKASHAN|Exercise Exercise 3d|35 Videos
  • LINEAR EQUATIONS IN TWO VARIABLES

    NAGEEN PRAKASHAN|Exercise Exercise 3a|18 Videos
  • INTRODUCTION TO TRIGONOMETRY

    NAGEEN PRAKASHAN|Exercise Revision Exercise Long Answer Questions|5 Videos
  • POLYNOMIALS

    NAGEEN PRAKASHAN|Exercise Revision Exercise Long Answer Questions|4 Videos

Similar Questions

Explore conceptually related problems

y-1=m_1(x-3) and y - 3 = m_2(x - 1) are two family of straight lines, at right angled to each other. The locus of their point of intersection is: (A) x^2 + y^2 - 2x - 6y + 10 = 0 (B) x^2 + y^2 - 4x - 4y +6 = 0 (C) x^2 + y^2 - 2x - 6y + 6 = 0 (D) x^2 + y^2 - 4x - by - 6 = 0

Let number of points of intersection and number of common tangents of two circles x^(2) + y^(2) - 6x - 2y + 1 = 0 and x^(2) + y^(2) + 2x - 6y + 9 = 0 be m and n respectively. Which of the following is/are

x - 2y + 2 = 0, 2x + y - 6= 0

If line 2x - y + k = 0 is a diameter of circle x^(2) + y^(2) + 6x - 6y + 5 = 0 , then k =

Consider the circles x^(2) + y^(2) = 1 & x^(2) + y^(2) – 2x – 6y + 6 = 0 . Then equation of a common tangent to the two circles is

The equation of the circle which inscribes a suqre whose two diagonally opposite vertices are (4, 2) and (2, 6) respectively is : (A) x^2 + y^2 + 4x - 6y + 10 = 0 (B) x^2 + y^2 - 6x - 8y + 20 = 0 (C) x^2 + y^2 - 6x + 8y + 25 = 0 (D) x^2 + y^2 + 6x + 8y + 15 = 0

Equation of tangents drawn from (0, 0) to x^(2) + y^(2) - 6x -6y + 9 = 0 are