Home
Class 10
MATHS
2(a x-b y)+(a+4b)=0 , 2(b x+a y)+(b-4a)...

`2(a x-b y)+(a+4b)=0 , 2(b x+a y)+(b-4a)=0`

Text Solution

Verified by Experts

The correct Answer is:
`x = - (1)/(2), y = 2`
Promotional Banner

Topper's Solved these Questions

  • LINEAR EQUATIONS IN TWO VARIABLES

    NAGEEN PRAKASHAN|Exercise Exercise 3d|35 Videos

  • LINEAR EQUATIONS IN TWO VARIABLES

    NAGEEN PRAKASHAN|Exercise Exercise 3e|56 Videos

  • LINEAR EQUATIONS IN TWO VARIABLES

    NAGEEN PRAKASHAN|Exercise Exercise 3b|30 Videos

  • INTRODUCTION TO TRIGONOMETRY

    NAGEEN PRAKASHAN|Exercise Revision Exercise Long Answer Questions|5 Videos

  • POLYNOMIALS

    NAGEEN PRAKASHAN|Exercise Revision Exercise Long Answer Questions|4 Videos

Similar Questions

Explore conceptually related problems

Factorise the using the identity a ^(2) -b ^(2) = (a +b) (a-b). (x + y) ^(4) - (x - y)^(4)

Factorise the using the identity a ^(2) -b ^(2) = (a +b) (a-b). x ^(4) - y ^(4) + x ^(2) - y ^(2)

L_1=(a-b)x+(b-c)y+(c-a)=0L_2=(b-c)x+(c-a)y+(a-b)=0L_3=(c-a)x+(a-b)y+(b-c)=0 KAMPLE 6 Show that the following lines are concurrent L1 = (a-b) x + (b-c)y + (c-a) = 0 12 = (b-c)x + (c-a) y + (a-b) = 0 L3 = (c-a)x + (a-b) y + (b-c) = 0. ,

Two straight lines are perpendicular to each other. One of them touches the parabola y^2=4a(x+a) and the other touches y^2=4b(x+b) . Their point of intersection lies on the line. x-a+b=0 (b) x+a-b=0 x+a+b=0 (d) x-a-b=0

If the origin is shifted to the point ((a b)/(a-b),0) without rotation, then the equation (a-b)(x^2+y^2)-2a b x=0 becomes (A)(a-b)(x^2+y^2)-(a+b)x y+a b x=a^2 (B)(a+b)(x^2+y^2)=2a b (C)(x^2+y^2)=(a^2+b^2) (D)(a-b)^2(x^2+y^2)=a^2b^2

((a-b)^2-(a+b)^2)/(-4a)=x/y . On simplifying the given equation, which of the following equations will be obtained? x y=b (b) b x=y (c) a b=x (d) y b=x (e) a y=x

Three sides of a triangle are represented by lines whose combined equation is (2x+y-4) (xy-4x-2y+8) = 0 , then the equation of its circumcircle will be : (A) x^2 + y^2 - 2x - 4y = 0 (B) x^2 + y^2 + 2x + 4y = 0 (C) x^2 + y^2 - 2x + 4y = 0 (D) x^2 + y^2 + 2x - 4y = 0