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Solve: a x+b y=c ,\ \ \ \ b x+a y=1+c...

Solve: `a x+b y=c ,\ \ \ \ b x+a y=1+c`

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The correct Answer is:
`x = (ac - b - bc)/(a^(2) - b^(2)), y = (bc - a- ac)/(b^(2) - a^(2))`
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