Home
Class 10
MATHS
{:(2x + 3y = 2),((k + 2)x + (2k + 1)y = ...

`{:(2x + 3y = 2),((k + 2)x + (2k + 1)y = 2(k - 1)):}`

Text Solution

Verified by Experts

The correct Answer is:
k = 4
Promotional Banner

Topper's Solved these Questions

  • LINEAR EQUATIONS IN TWO VARIABLES

    NAGEEN PRAKASHAN|Exercise Exercise 3e|56 Videos

  • LINEAR EQUATIONS IN TWO VARIABLES

    NAGEEN PRAKASHAN|Exercise Revision Exercise Very Short Answer Questions|9 Videos

  • LINEAR EQUATIONS IN TWO VARIABLES

    NAGEEN PRAKASHAN|Exercise Exercise 3c|15 Videos

  • INTRODUCTION TO TRIGONOMETRY

    NAGEEN PRAKASHAN|Exercise Revision Exercise Long Answer Questions|5 Videos

  • POLYNOMIALS

    NAGEEN PRAKASHAN|Exercise Revision Exercise Long Answer Questions|4 Videos

Similar Questions

Explore conceptually related problems

{:(2x + (k - 2)y = k),(6x + (2k - 1) y = 2k + 5):}

Find the values of k for which the following pair of linear equations has infinitely many solutions : 2x - 3y = 7, ( k + 1 ) x + ( 1 - 2k) y = ( 5k - 4) .

5x + 2y = 2k , 2 (k + 1 ) x + ky = (3k + 4)

det [[x ^ (k), x ^ (k + 2), x ^ (k + 3) y ^ (k), y ^ (k + 2), y ^ (k + 3) z ^ (k) , z ^ (k + 2), z ^ (k + 3)]] = (xy) (yz) (zx) {(1) / (x) + (1) / (y) + (1) / ( from)}

If the lines (x -1)/(-3) = (x - 2)/(2k) = (z - 3)/(2) and (x - 1)/(3k ) = (y -1)/(1) = (z - 6)/(-5) are perpendicular to each other, then the value of k is ,

Find the value of k for which following system of equations have infinitely many solution: 2x+3y=2,quad (k+2)x+(2k+1)y=2(k-1)

if the lines (x - 1)/(-3) = ( y - 2)/(2k) = ( z -3)/(2) and (x -1) /(3k) = ( y - 5)/(1) = (z - 6 ) /(-5) are at night angle , then find the value of k .

For what the value of k, the following pair of linear equations have infinitely many solutions : 2x + 3y= 7 and (k+1) x + (2k-1)y= 4k+1

If K is constant such that xy + k = e ^(((x-1)^2)/(2)) satisfies the differential equation x . ( dy )/( dx) = (( x^2 - x-1) y+ (x-1) and y (1) =0 then find the value of K .