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A and B together can do a piece of work in 15 days. If 1 day's work of A be `1(1)/(2)` times one day's work of B. Find in how many days each alone will do the work.

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The correct Answer is:
A alone in 25 days and B alone in 37.5 days.
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A and B together can do a piece of work in 10 days. If A alone can do the work in 15 days, find in how many days that B alone can do the same work. The following are the steps involved in solving the above problem. Arrange them in sequential order. One day's work of B is (1)/(10)-(1)/(5) . One day's work of A and B is (1)/(10) and one day's work of A is (1)/(15) . B alone can do the work in 30 days. One day's work of B is (1)/(30) .

A and B together can do a piece of work in 10 days. If A alone can do the work in 15 days, find in how many days that B alone can do the same work. The following are the steps involved in solving the above problem. Arrange them in sequential order. One day's work of B is (1)/(10)-(1)/(5) . One day's work of A and B is (1)/(10) and one day's work of A is (1)/(15) . B alone can do the work in 30 days. One day's work of B is (1)/(30) .

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NAGEEN PRAKASHAN-LINEAR EQUATIONS IN TWO VARIABLES -Exercise 3e
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