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As observed from the top of a light hous...

As observed from the top of a light house, 100 m high above sea level, the angles of depression of a ship, sailing sirectly towards it, changes from `30^(@)" and "90^(@)`.

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Let the height of light house be AB=100 m and let D be the ship which is sailing towards it. Also let DC = x m.
Here, `angleCAD=60^(@)-30^(@)=30^(@)`
`:. angleCDA=angleCAD" (each "30^(@)`)
`:. DC=AC=x …(1)`
(angles opposite to equal sides are equal)
Now, in right `DeltaABC`, ,brgt `sin60^(@)=(AB)/(AC)rArrsqrt3/2=100/(DC) [from(1)]`
`rArr DC=200/sqrt3=(200sqrt3)/3=(200xx1.73)/3`
`:. DC =346/3=115.3 m`
Hence, distance travelled by ship is 115.3 m.
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