Factorise x^(2)-(y-z)^(2)....

Factorise `x^(2)-(y-z)^(2)`.

`(x+y-z)(x+y+z)`

`(x+y-z)(x-y-z)`

`(x-y-z)(x-y+z)`

`(x+y-z)(x-y+z)`

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The correct Answer is:

Given expression : `(x)^(2)-(y-z)^(2)=[x(y-z)][x-(y-z)] " " [because x^(2)-y^(2)=(x+y)(x-y)]`
=(x+y-z)(x-y+z)

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