Home
Class 9
MATHS
Factorise : (i) 125a^(3)+(1)/(8) " ...

Factorise : `(i) 125a^(3)+(1)/(8) " " (ii) 8a^(3)-27b^(3)`

Text Solution

Verified by Experts

`(i) 125a^(3)+(1)/(8)=(5a)^(3)+((1)/(2))^(3)`
`=x^(3)+y^(3) " " ("where" x=5a " and" y=(1)/(2))`
`=(x+y)(x^(2)+y^(2))`
`=(5a+(1)/(2))(25a^(2)-(5)/(2)a+(1)/(4))`
`(ii) 8a^(3)-27b^(3)=(2a)^(3)-(3b)^(3)`
`=x^(3)-y^(3) " " ("where" x=2a " and" y=3b)`
`=(x-y)(x^(2)+xy+y^(2))`
`=(2a-3b)(4a^(2)+6ab+9b^(2))`
Promotional Banner

Topper's Solved these Questions

  • POLYNOMIALS

    NAGEEN PRAKASHAN|Exercise Problems From NCERT/exemplar|18 Videos

  • POLYNOMIALS

    NAGEEN PRAKASHAN|Exercise Exercise 2a|8 Videos

  • NUMBER SYSTEM

    NAGEEN PRAKASHAN|Exercise Revision Exercise (short Answer Questions)|10 Videos

  • PROBABILITY

    NAGEEN PRAKASHAN|Exercise Revision Exercise (very Short Answer /short Answer Questions)|10 Videos

Similar Questions

Explore conceptually related problems

Factorize: 27a^(3)+125b^(3)

Factorise : a^(3) +8/27 b^(3)

Factorise: 18a^(3) -27a^(2)b

Factorise : x-8xy^(3)

factorise x^(6)+5x^(3)+8

Factorise : (i) 9a^(3)-27b^(3) " " (ii) a^(3)-343 " " (iii) a^(3)-(27)/(a^(3)) " " (iv) 1+8a^(3) " " (v) (a+b)^(3)-(a-b)^(3) .

Factorise (x+y)^(3)-27z^(3)

Factorise: 27 a ^(3) - b ^(3) - 1 - 9 ab

Factorise: 3z ^(2) - 10z + 8