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If a+b+c=2, ab+bc+ca=-1 and abc=-1 and a...

If a+b+c=2, ab+bc+ca=-1 and abc=-1 and abc=-2 , find the value of `a^(3)+b^(3)+c^(3)`.

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To find the value of \( a^3 + b^3 + c^3 \) given the equations \( a + b + c = 2 \), \( ab + bc + ca = -1 \), and \( abc = -2 \), we can use the identity that relates these expressions. ### Step-by-Step Solution: 1. **Use the identity for the sum of cubes**: \[ a^3 + b^3 + c^3 - 3abc = (a + b + c)(a^2 + b^2 + c^2 - ab - ac - bc) \] ...
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