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Simplify (2x-5y)^(3)-(2x+5y)^(3)....

Simplify `(2x-5y)^(3)-(2x+5y)^(3)`.

A

`120x^(2)y-250y^(3)`

B

`120x^(2)y+250y^(3)`

C

`-120x^(2)y-250y^(3)`

D

can not determine its value

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The correct Answer is:
To simplify the expression \((2x - 5y)^3 - (2x + 5y)^3\), we can use the identity for the difference of cubes: \[ A^3 - B^3 = (A - B)(A^2 + AB + B^2) \] Here, let: - \(A = (2x - 5y)\) - \(B = (2x + 5y)\) ### Step 1: Calculate \(A - B\) \[ A - B = (2x - 5y) - (2x + 5y) = 2x - 5y - 2x - 5y = -10y \] ### Step 2: Calculate \(A^2\) \[ A^2 = (2x - 5y)^2 = (2x)^2 - 2 \cdot (2x)(5y) + (5y)^2 = 4x^2 - 20xy + 25y^2 \] ### Step 3: Calculate \(B^2\) \[ B^2 = (2x + 5y)^2 = (2x)^2 + 2 \cdot (2x)(5y) + (5y)^2 = 4x^2 + 20xy + 25y^2 \] ### Step 4: Calculate \(AB\) \[ AB = (2x - 5y)(2x + 5y) = (2x)^2 - (5y)^2 = 4x^2 - 25y^2 \] ### Step 5: Combine \(A^2\), \(AB\), and \(B^2\) Now we can combine these results: \[ A^2 + AB + B^2 = (4x^2 - 20xy + 25y^2) + (4x^2 - 25y^2) + (4x^2 + 20xy + 25y^2) \] Combine like terms: \[ = 4x^2 + 4x^2 + 4x^2 + (-20xy + 20xy) + (25y^2 - 25y^2) \] \[ = 12x^2 \] ### Step 6: Substitute back into the difference of cubes formula Now substituting back into the difference of cubes formula: \[ (2x - 5y)^3 - (2x + 5y)^3 = (A - B)(A^2 + AB + B^2) = (-10y)(12x^2) \] ### Step 7: Final result Thus, the simplified expression is: \[ = -120xy \]

To simplify the expression \((2x - 5y)^3 - (2x + 5y)^3\), we can use the identity for the difference of cubes: \[ A^3 - B^3 = (A - B)(A^2 + AB + B^2) \] Here, let: - \(A = (2x - 5y)\) ...
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