Verify :
`(i) x^(3)+y^(3)=(x+y)(x^(2)-xy+y^(2)) " " (ii) x^(3)-y^(3)=(x-y)(x^(2)+xy+y^(2))`

Veriffy : (i) x^(3)+y^(3)=(x+y)(x^(2)-xy+y^(2))x^(3)-y^(3)=(x-y)(x^(2)+xy+y^(2))

The following are the steps involved in factorizing 64 x^(6) -y^(6) . Arrange them in sequential order (A) {(2x)^(3) + y^(3)} {(2x)^(3) - y^(3)} (B) (8x^(3))^(2) - (y^(3))^(2) (C) (8x^(3) + y^(3)) (8x^(3) -y^(3)) (D) (2x + y) (4x^(2) -2xy + y^(2)) (2x - y) (4x^(2) + 2xy + y^(2))

x^(3) + x^(2)y+ xy^(2) + y^(3) = 81

x^(3)+x^(2)y+xy^(2)+y^(3)

If log_(10)|x^(3)+y^(3)|-log_(10)|x^(2)-xy+y^(2)|+log_(10)|x^(3)-y^(3)|-log_(10)|x^(2)+xy+y^(2)|=log_(10)221 . Where x, y are integers, then Q. If y=2 , then value of x can be :

The factors of x^(3)-x^(2)y-xy^(2)+y^(3) are (a (x+y)(x^(2)-xy+y^(2))(b)(x+y)(x^(2)+xy+y^(2))(c)(x+y)^(2)(x-y)(d)(x-y)^(2)(x+y)

x^(3) + xy^(2) - x^(2) y - y^(3) = "_______"

Divide: (i) 6x^(5) + 18 x^(4) - 3x^(2) by 3x^(2) (ii) 20 x^(3) y + 12 x^(2) y^(2) - 10 xy by 2xy