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Find the product : (i) (x+3)(x^(2)-3x+...

Find the product :
`(i) (x+3)(x^(2)-3x+9) " " (ii) (7+5b)(49-35b+25b^(2))`
`(iii) (5a+(1)/(2)) (25a^(2)-(5a)/(2)+(1)/(4)) " " (iv) (a+b-2)[a^(2)+b^(2)+2ab+2(a+b)+4]`.

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Let's solve the given products step by step. ### (i) Find the product: \((x+3)(x^2-3x+9)\) 1. **Identify the terms**: We have \(A = x\) and \(B = 3\). 2. **Recognize the identity**: This expression resembles the identity for \(A^3 + B^3\), where: \[ A^3 + B^3 = (A + B)(A^2 - AB + B^2) \] 3. **Calculate \(A^3\) and \(B^3\)**: - \(A^3 = x^3\) - \(B^3 = 3^3 = 27\) 4. **Calculate \(AB\)**: - \(AB = x \cdot 3 = 3x\) 5. **Substitute into the identity**: \[ (x + 3)(x^2 - 3x + 9) = x^3 + 27 \] **Final Answer for (i)**: \(x^3 + 27\) --- ### (ii) Find the product: \((7 + 5b)(49 - 35b + 25b^2)\) 1. **Identify the terms**: Here, \(A = 7\) and \(B = 5b\). 2. **Recognize the identity**: This also resembles \(A^3 + B^3\): \[ A^3 + B^3 = (A + B)(A^2 - AB + B^2) \] 3. **Calculate \(A^3\) and \(B^3\)**: - \(A^3 = 7^3 = 343\) - \(B^3 = (5b)^3 = 125b^3\) 4. **Calculate \(AB\)**: - \(AB = 7 \cdot 5b = 35b\) 5. **Substitute into the identity**: \[ (7 + 5b)(49 - 35b + 25b^2) = 343 + 125b^3 \] **Final Answer for (ii)**: \(343 + 125b^3\) --- ### (iii) Find the product: \(\left(5a + \frac{1}{2}\right)\left(25a^2 - \frac{5a}{2} + \frac{1}{4}\right)\) 1. **Identify the terms**: Here, \(A = 5a\) and \(B = \frac{1}{2}\). 2. **Recognize the identity**: This expression resembles \(A^3 + B^3\): \[ A^3 + B^3 = (A + B)(A^2 - AB + B^2) \] 3. **Calculate \(A^3\) and \(B^3\)**: - \(A^3 = (5a)^3 = 125a^3\) - \(B^3 = \left(\frac{1}{2}\right)^3 = \frac{1}{8}\) 4. **Calculate \(AB\)**: - \(AB = 5a \cdot \frac{1}{2} = \frac{5a}{2}\) 5. **Substitute into the identity**: \[ \left(5a + \frac{1}{2}\right)\left(25a^2 - \frac{5a}{2} + \frac{1}{4}\right) = 125a^3 + \frac{1}{8} \] **Final Answer for (iii)**: \(125a^3 + \frac{1}{8}\) --- ### (iv) Find the product: \((a + b - 2)(a^2 + b^2 + 2ab + 2(a + b) + 4)\) 1. **Identify the terms**: Here, let \(A = a + b\) and \(B = 2\). 2. **Recognize the identity**: This resembles \(A^3 - B^3\): \[ A^3 - B^3 = (A - B)(A^2 + AB + B^2) \] 3. **Calculate \(A^3\) and \(B^3\)**: - \(A^3 = (a + b)^3\) - \(B^3 = 2^3 = 8\) 4. **Substitute into the identity**: \[ (a + b - 2)((a + b)^2 + 2(a + b) + 4) = (a + b)^3 - 8 \] **Final Answer for (iv)**: \((a + b)^3 - 8\) ---
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NAGEEN PRAKASHAN-POLYNOMIALS-Exercise 2 E
  1. Evaluate without multiplying directly : (i) 33xx27 " " (ii) 103xx9...

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  2. Expand : (i) (3a-5b)^(2) " " (ii) (a+(1)/(a))^(2) " " (iii) (2x-(...

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  3. Expand : (i) (a+b-c)^(2) " " (ii) (a-2b-5c)^(2) " " (iii) (3a-2b...

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  4. Evaluate using formula : (i) (188)^(2) " " (ii) (9.4)^(2) " " (i...

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  5. (i) If a^(2)+b^(2)+c^(2)=20 " and" a+b+c=0, " find " ab+bc+ac. (ii) ...

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  6. Expand : (i) (2x+3y)^(3) " " (ii) (5y-3x)^(3) " " (iii) (2a+3b)...

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  7. Evaluate (2x-3y+5)^(3).

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  8. If a+2b=5, then show that a^(3)+8b^(3)+30ab=125.

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  9. If 2x-3y=10 and xy=16, find the value of 8x^(3)-27y^(3).

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  10. Evaluate : (i) (98)^(3) " " (ii) (598)^(3) " " (iii) (1003)^(3)

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  11. Factorise : (i) 4a^(2)+9b^(2)+16c^(2)+12ab-24bc-16ca (ii) (4)/(9)x...

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  12. Verify : (i) x^(3)+y^(3)=(x+y)(x^(2)-xy+y^(2)) " " (ii) x^(3)-y^(...

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  13. Factorise : (i) 9a^(3)-27b^(3) " " (ii) a^(3)-343 " " (iii) a^(...

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  14. Find the product : (i) (x+3)(x^(2)-3x+9) " " (ii) (7+5b)(49-35b+2...

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  15. Factorise : (i) a^(3)+27b^(3)+8c^(3)-18abc " " (ii) 2sqrt(2)a^(3)...

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  16. Find the product : (i) (a+2b+4c)(a^(2)+4b^(2)+16c^(2)-2ab-8bc-4ca) ...

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  17. Factorise : (i) (x-y)^(3)+(y-z)^(3)+(z-x)^(3) (ii) (x-2y)^(3)+(2y-...

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  18. Without actually calculating the cube find the value of the following ...

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  19. Verify that x^(3)+y^(3)+z^(3)-3xyz=(1)/(2)(x+y+z)[(x-y)^(2)+(y-z)^(2)+...

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  20. If x+y+z=0show that x^3+y^3+z^3=3x y z.

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