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In the adjoining figure O is the centre ...

In the adjoining figure `O` is the centre of the circle . If chord `AB=2` cm radius `OA=2` cm, then find the value of `angle ACB`.

A

`=60^@`

B

`=45^@`

C

`=30^@`

D

`=50^@`

Text Solution

Verified by Experts

The correct Answer is:
C
Here, `OA =OB =2 cm`
and `AB=2cm`
`thereforeDeltaOAB` is an equilateral triangle.
`rArrtriangle AOB =60^(@)`
Now, angles subtended by arc `AB` at centre `=angleAOB`
remaining circle `=angle ACB`
`therefore angle ACB=(1)/(2)angle AOB`
`=(1)/(2)xx60^(@)`
`=30^@`
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