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In the figure, O D is perpendicula...

In the figure, `O D` is perpendicular to the chord `A B` of a circle whose centre is `Odot` If `B C` is a diameter, show that `C A=2O Ddot`

Text Solution

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Since, `ODbotAB` (given) and the perpendicular drawn from the centre to a chord bisects the chord.
`therefore` D is the mid -point of AB.
Also, O is the mid -point of BC.
Now, in `Delta ABC`, D and O are mid-points of AB and BC respectively.
Therefore, `OD|\ |AC` and `OD = 1//2 AC`.
or CA =2OD (mid-point theorem).
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