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Shanti sweets stall was placing an order...

Shanti sweets stall was placing an order for making cardboard boxes for packing their sweets. Two sizes of boxes were required. The bigger of dimensions `25cm xx 20cm xx 5 cm` and the smaller of dimensions `15cm xx 12cm xx 5cm`. For all the overlaps, `5%` of the total surface area is required for supplying `250` boxes of each kind.

A

`2184`

B

`4980`

C

`1900`

D

`9100`

Text Solution

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The correct Answer is:
To solve the problem of calculating the total surface area required for the cardboard boxes and the cost associated with them, we will follow these steps: ### Step 1: Calculate the Surface Area of the Bigger Box The dimensions of the bigger box are \(25 \, \text{cm} \times 20 \, \text{cm} \times 5 \, \text{cm}\). The formula for the surface area \(A\) of a rectangular box is given by: \[ A = 2(lw + lh + wh) \] where \(l\), \(w\), and \(h\) are the length, width, and height of the box respectively. Substituting the values: \[ A = 2(25 \times 20 + 25 \times 5 + 20 \times 5) \] Calculating each term: - \(25 \times 20 = 500\) - \(25 \times 5 = 125\) - \(20 \times 5 = 100\) Now substitute these back into the formula: \[ A = 2(500 + 125 + 100) = 2(725) = 1450 \, \text{cm}^2 \] ### Step 2: Calculate the Surface Area of the Smaller Box The dimensions of the smaller box are \(15 \, \text{cm} \times 12 \, \text{cm} \times 5 \, \text{cm}\). Using the same surface area formula: \[ A = 2(15 \times 12 + 15 \times 5 + 12 \times 5) \] Calculating each term: - \(15 \times 12 = 180\) - \(15 \times 5 = 75\) - \(12 \times 5 = 60\) Now substitute these back into the formula: \[ A = 2(180 + 75 + 60) = 2(315) = 630 \, \text{cm}^2 \] ### Step 3: Calculate the Total Surface Area for 250 Boxes of Each Kind For the bigger boxes: \[ \text{Total Surface Area for Bigger Boxes} = 250 \times 1450 = 362500 \, \text{cm}^2 \] For the smaller boxes: \[ \text{Total Surface Area for Smaller Boxes} = 250 \times 630 = 157500 \, \text{cm}^2 \] ### Step 4: Calculate the Combined Surface Area Now, add the surface areas of both types of boxes: \[ \text{Total Surface Area} = 362500 + 157500 = 520000 \, \text{cm}^2 \] ### Step 5: Add 5% for Overlaps To account for overlaps, calculate 5% of the total surface area: \[ \text{Overlap Area} = 0.05 \times 520000 = 26000 \, \text{cm}^2 \] Now add this to the total surface area: \[ \text{Total Surface Area with Overlaps} = 520000 + 26000 = 546000 \, \text{cm}^2 \] ### Step 6: Calculate the Cost The cost is given as \(4 \, \text{rupees for every 1000 cm}^2\). First, find the total cost: \[ \text{Cost} = \frac{546000}{1000} \times 4 = 546 \times 4 = 2184 \, \text{rupees} \] ### Final Answer The total cost for the cardboard boxes is **2184 rupees**. ---

To solve the problem of calculating the total surface area required for the cardboard boxes and the cost associated with them, we will follow these steps: ### Step 1: Calculate the Surface Area of the Bigger Box The dimensions of the bigger box are \(25 \, \text{cm} \times 20 \, \text{cm} \times 5 \, \text{cm}\). The formula for the surface area \(A\) of a rectangular box is given by: \[ ...
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