Parveen wanted to make a temporary shelter for her car, by making a box-like structure with tarpaulin that covers all the four sides and the top of the car (with the front face as a flap which can be rolled up). Assuming that the stitching margin

Explanation

Dimension for shelter, l = 4m, b =4m and h = 2.5 cm
Required area of tarpaulin to make the shelter
= (area of 4 sides + area of the top) of the car
`= 2(l+b)xxh+(lxxb)`
`{2(4+3)xx2.5+(4xx3)}m^(2)`
`={(2xx7xx2.5)+12}m^(2)=(35+12)m^(2)=47 m^(2)`