Find the equation of circle whose :
(i) radius is 5 and centre is (3,4).
(ii) radius is `sqrt(5)` and centre is (0.2).
(iii) radius is `sqrt(a^(2)+b^(2))` and centre is (a,b).
(iv) radius is r and centre is `(rcostheta,rsintheta)`.
(v) radius is `sqrt(a^(2)sec^(2)theta+b^(2)tan^(2)theta)` and centre is `(asectheta,btantheta)`.

Answer

(i) `x^(2)+y^(2)-6-8y=0` , (ii) `x^(2)+y^(2)-4y-1=0`
(iii) `x^(2)+y^(2)-2ar-2by=0`
(iv) `x^(2)+y^(2)-2rcostheta*x-2rsintheta*y=0`
(v) `x^(2)+y^(2)-2axsectheta-2bytantheta=0`