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Find the equation of hyperbola whose tra...

Find the equation of hyperbola whose transverse axis is 10 conjugate axis is 6.

Text Solution

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The correct Answer is:
`(x^(2))/(25)-(y^(2))/(9)=1`
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Find the equation of the hyperbola whose axes (transverse and conjugate axis) are parallel to x axis and y axis and centre is origin.Length of latus rectum lengthis 18 unit and distance between focies is 12unit.

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Knowledge Check

  • For hyperbola, If transverse axis = conjugate axis , then e =

    A
    0
    B
    1
    C
    2
    D
    `sqrt(2)`

  • Find the equation of hyperbola where, conjugate axis is 3 along Y-axis and distance between foci is 5.

    A
    `(4x^(2))/(9) - (y^(2))/(4) = 1`
    B
    `(x^(2))/(4) - (4y^(2))/(9) = 1`
    C
    `(x^(2))/(4) - (y^(2))/(9) = 1`
    D
    `4x^(2) - 36y^(2) = 9`

  • Find the equation of hyperbola whose conjugate axis = latus-rectum = 8 ,

    A
    ` 16x^(2) - 16y^(2) = 1`
    B
    `16x^(2) - 16y^(2) = -1`
    C
    `x^(2) - y^(2) = 16`
    D
    `8x^(2) - 8y^(2) = 1`

    • Similar Questions

    Explore conceptually related problems

    Find the equation of the hyperbola whose foci are (+-5,0) and the conjugate axis is of the length 8. Also ,Find its eccentricity .

    Find the equation of the hyperbola in which the length of conjugate axis is 5 and the distance between foci is 13.

    Find the equation of the hyperbola whose conjugate axis is 5 and the distance between the foci is 13.

    Find the equation of the parabola whose vertex is at (2,-3), axis is parallel to x -axis and length of latus rectum is 12

    Find the equation of hyperbola : Whose center is (1,0), focus is (6,0) and the transverse axis is 6

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