Home
Class 11
MATHS
Focus (6,0), directrix x=-6...

Focus (6,0), directrix x=-6

Text Solution

AI Generated Solution

To find the equation of the parabola given the focus at (6, 0) and the directrix x = -6, we can follow these steps: ### Step 1: Understand the definition of a parabola A parabola is defined as the set of all points (P) that are equidistant from the focus and the directrix. ### Step 2: Identify the focus and directrix - Focus (S) = (6, 0) - Directrix = x = -6 ...
Promotional Banner

Topper's Solved these Questions

  • CONIC SECTION

    NAGEEN PRAKASHAN|Exercise Exercise 11.3|20 Videos
  • CONIC SECTION

    NAGEEN PRAKASHAN|Exercise Exercise 11.4|15 Videos
  • CONIC SECTION

    NAGEEN PRAKASHAN|Exercise Exercise 11.1|15 Videos
  • COMPLEX NUMBERS AND QUADRATIC EQUATION

    NAGEEN PRAKASHAN|Exercise MISCELLANEOUS EXERCISE|20 Videos
  • INTRODUCTION OF THREE DIMENSIONAL GEOMETRY

    NAGEEN PRAKASHAN|Exercise Miscellaneous Exercise|6 Videos

Similar Questions

Explore conceptually related problems

Focus (0,-3), directrix y=3

Find the equation of the parabola that satisfies the given conditions: Focus (6,quad 0); directrix x=-6

The equation of the parabola with the focus (3,0) and directrix x+3=0 is

The equation of a parabola having focus (3, 0) and directrix x + 3 = 0, is

Find the equation of the parabola with focus (2,0) and directrix x=-2

Write the equation of the parabola with focus (0,0) and directrix x+y-4=0

Find the equation of the hyperbola whose : focus (a,0), directrix is 2x-y+a=0 and eccentricity =(4)/(3)

Equation of the ellipse whose focus is (6,7) directrix is x+y+2=0 and e=(1)/(sqrt(3)) is-

Find the equation of the ellipse whose : One focus is (6, 7) , directrix is x + y + 2 and eccentricity is 1/sqrt(3)