Find the differential coefficient of `a.x^(2) sin x` with respect to 'x' .

Explanation

Let `y=a.x^(2).sinx`
`rArr(dy)/(dx)=a.(dx)(x^(2)sinx)`
`=a[x^(2)(d)/(dx)sinx+sinx(d)/(Dx)x^(2)]`
`=a[x^(2).cosx+sinx.2x]`
`=a.x[xcos x+22 sinx]`.