Differentiate `(e^(x)cos x+x^(2)"log"x)`
with respect to 'x'.

Explanation

Let `y=e^(x)cos x+x^(2)"log"x`
`rArr (dy)/(dx)=(d)/(dx)(e^(x)cos x+x^(2)"log"x)`
`=(d)/(dx)(e^(x)cos s)+(d)/(dx)(x^(2)"log"x)`
`=e^(x)(d)/(dx)c os x+cos x(d)/(dx)e^(x)`
`+x^(2)(d)/(dx)"log"x+log"x(d)/(dx)x^(2)`
`=-e^(x)sin x+cos x.e^(x)`
`+x^(2).(1)/(x)+"log"x.(2x)`
`=e^(x)(cos x-sinx)+x+2x"log"x`