`cos x`

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1+ cos 2x+ cos4x + cos 6x=

lim_(x->0) (cos2x-cos4x)/(cos3x-cos5x) =

Prove that 2cosx. Cos 3x- 2cos 5x. Cos 7x- cos 4x + cos12x=0 .

If cos3x+cos6x=cos4x+cos5x, then the solution set is

cos4x cos8x-cos5x cos9x=0 if

int(cos7x-cos8x)/(cos2x-cos3x)dx

cos2x-cos8x+cos6x=1

Prove that: (cos7x-cos8x)/(1+2cos5x)=cos2x-cos3x

cos^(12)x+3cos^(10)x+3cos^(8)x+cos^(6)x-2