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tan^(-1)((cosx-sinx)/(cosx+sinx))=pi/4-x...

`tan^(-1)((cosx-sinx)/(cosx+sinx))=pi/4-x`

Text Solution

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`tan^(-1)((cosx-sinx)/(cosx+sinx))`
`=tan^(-1)""(((cosx)/(cosx)-(sinx)/(cosx))/((cosx)/(cosx)+(sinx)/(cosx)))`
`tan^(-1)((1-tanx)/(1+tanx))`
`= tan^(-1){tan((pi)/(4)-x)}=(pi)/(4)-x`
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