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The position of and object moving along x-axis is gi en by `x=a +bt^(2)`, wher `a=8.5 m` and b=2.5 ms^(-2) and (t) is measured in ceconds. What is the velcoity `at t=1= 0`s and `t=2.0 s?` What is the average velocity between `t=2.0s` and `t=4.0 s`?

A

`5 m s^(-1)`

B

`10 m s^(-1)`

C

`15 m s^(-1)`

D

`20 m s^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
Here, x = `a + bt^(2)`
Where, a = 8.5 m and b = `2.5 m s^(-2)`
Velocity, `v = dx/dt = d/dt(a + bt^(2)) = 2bt`
At t = 2 s,
`v = 2(2.5 m s^(-2))(2 a) = 10 m s^(-2)`
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