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A girl standing on a stationary lift (op...

A girl standing on a stationary lift (open from above) throws a ball upwards with initial speed `50 m s^(-1)`. The time taken by the ball to return to her hands is (Take g = `10 m s^(-2)`)

A

5 s

B

10 s

C

15 s

D

20 s

Text Solution

Verified by Experts

The correct Answer is:
B
Using, S = `ut + 1/2 at^(2)`
Here S = 0, u = `50 m s^(-1)`, a = - g = `- 10 m s^(-2)`
`therefore 0 = 50t + 1/2 xx (-10)t^(2) = 50t - 5t^(2) impliest = 10` s
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Knowledge Check

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