A particle is moving on a circular path of radius R with constant speed v. During motion of the particle form point A to point B

Options

A. Average speed is v/2
B. The magnitude of average velocity is v/`pi`
C. The magnitude of average acceleration is `(2v^(2))/(piR)`
D. Average velocity is zero.

Answer

(c )

Explanation

(a) Average velocity `= ("Displacement") /("Total elapsed time") = 2 R// pi R//v = 2v//pi`
(b) Average speed `= ("Total distance") /("Total elapsed time") = (piR)/((piR)/v) = v`
(c ) Average acceleration
`= (v_f -v_i)/ "Total elapsed time" = (2v)/((piR)/v) = (2v^(2))/(piR)`