Home
Class 11
PHYSICS
The centre of mass of a system of two pa...

The centre of mass of a system of two particle of masses `m_1 and m_2` is at a distance `d_1` from mass `m_1` and at a distance `d_2` from mass `m_2` such that.

A

`d_1/d_2 = m_2/m_1`

B

`d_1/d_2 = m_1/m_2`

C

`d_1/d_2 = m_1/m_1 + m_2`

D

`d_1/d_2 = m_2/m_1 + m_2`

Text Solution

Verified by Experts

The correct Answer is:
A
Refer figure,
The distance of center of mass CM from masses `m_(1)` and `m_(2)` are
`d_(1)=(m_(2)d)/(m_(1)+m_(2))` and `d_(2)=(m_(1)d)/(m_(1)+m_(2))` `therefore d_(1)/d_(2)=m_(2)/m_(1)`
Promotional Banner

Topper's Solved these Questions

  • SYSTEM OF PARTICLES AND ROTATIONAL MOTIONS

    NCERT FINGERTIPS|Exercise Motion Of Centre Of Mass|10 Videos

  • SYSTEM OF PARTICLES AND ROTATIONAL MOTIONS

    NCERT FINGERTIPS|Exercise Torque And Angular Momentum|11 Videos

  • SYSTEM OF PARTICLES AND ROTATIONAL MOTIONS

    NCERT FINGERTIPS|Exercise Assertion And Reason|15 Videos

  • PRACTICE PAPERS

    NCERT FINGERTIPS|Exercise Practice Paper 3|50 Videos

  • THERMAL PROPERTIES OF MATTER

    NCERT FINGERTIPS|Exercise Assertion And Reason|10 Videos

Similar Questions

Explore conceptually related problems

The centre of mass of a system of two particle of masses m_1 and m_2 is at a distance d_1 from m_1 and at a distance d_2 from mass m_2 such that.

The centre of mass of a system of two particles of masses m_(1) and m_(2) is at a distance d_(1) from m_(1) and at a distance d_(2) from mass m_(2) such

Two bodies of masses m_1 and m_2(

Calculate the position of centre of mass of a system consisting of two particles of masses m_1 and m_2 separated by a distance L apar, from m_1?

The position of centre of mass of a system consisting of two particles of masses m_(1) and m_(2) seperated by a distance L apart , from m_(1) will be :

Consider a system of two particles having masses m_(1) and m_(2) . If the particle of mass m_(1) is pushed towards the centre of mass of particles through a distance d , by what distance would the particle of mass m_(2) move so as to keep the mass centre of particles at the original position?

There are two masses m_1 and m_2 placed at a distance l apart. Let the centre of mass of this system is at a point named C. If m_1 is displaced by l_1 towards C and m_2 is displaced by l_2 away from C. Find the distance, from C where new centre of mass will be located.

If vec(R)_(CM) is the position of the centre of mass of a system of two particles of masses m_(1) and m_(2) then vec(R)_(CM) is given by :

The centre of masses of three particles of mass m_(1) = m_(2)=m_3 = 1 kg at the corners of an equilateral triangle of side 1 m will be -