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An automobile engine develops 100 kilo-w...

An automobile engine develops `100` kilo`-`watt, when rotating at a speed of `1800 rev//min`. Find the torque developed by it.

A

`10^(2)/6pi` N m

B

`10^(4)/6pi` N m

C

`10^(6)/6pi` N m

D

`10^(8)/6pi` N m

Text Solution

Verified by Experts

The correct Answer is:
b
Initial angular speed,
`omega_(0)=(2pi xx 1200)/(60)rad s^(-1)= 40pirads^(-1)`
`therefore` Angular acceleration,
`alpha = (omega-omega_(0))/(t) = (104pi-40pi)/(16)`rps =30 rps
`therefore omega=2piv=2pi(30)=60pi rad s^(-1)`
As `P=tauomega`
`therefore tau=P/omega=(10^(5)W)/(60 pi rad s^(-1)) = (10^(4))/(6 pi) Nm`
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Knowledge Check

  • An automobile engine develops 100kW when rotating at a speed of 1800 rev/min. What torque does it deliver

    A
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    B
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