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The instantaneous angular position of a ...

The instantaneous angular position of a point on a rotating wheel is given by the equation
`theta(t) = 2t^(3) - 6 t^(2)`
The torque on the wheel becomes zero at

A

t = 1 s

B

t = 0.5 s

C

t = 0.25 s

D

t = 2 s

Text Solution

Verified by Experts

The correct Answer is:
A
Given, `theta(t)= 2t^(2)-6t^(2)`
`therefore (d(theta))/(dt) = 6t^(2)-12t, (d^(2)theta)/(dt^(2))=12t-12`
Angular acceleration, `alpha=(d^(2)theta)/(dt^(2))=12t-12`
When angular acceleration `(alpha)` is zero, then the torque on the wheel becomes zero
`rArr 12t-12=0` or t=1s
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