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Leg f(x)=x^4-4x^3+6x^2-4x+1. Then, f inc...

Leg `f(x)=x^4-4x^3+6x^2-4x+1.` Then, `f` increase on `[1,oo]` `f` decreases on `[1,oo]` `f` has a minimum at `x=1` `f` has neither maximum nor minimum

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