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What amount of heat must be supplied to 35 g of oxygen at room temperature to raise its temperature by `80^(@)C` at constant volume (molecular mass of oxygen is 32 and R= 8.3 `j mol^(-1) K^(-1)`

A

1.52 KJ

B

3.23 KJ

C

1.81 KJ

D

1.62 KJ

Text Solution

Verified by Experts

The correct Answer is:
C

Here mass of oxygen (m) =35 g
molar mass of `O_(2)(M)=32 g mol^(-1)`
rise in temperature ,`Delta)T=80^(@)C`
number of moles `n=(m)/(M)=(35)/(32)`=1.09 mol
As oxygen is a diatomeic gas then molar specific heat at
constant volume is `C_(V)=(5)/(2)R`
and amount of heat supplied to gas
`DeltaQ =nC_(V)DeltaT=1.09 xx(5)/(2)Rxx80 =1.09xx(5)/(2)xx8.3xx80`
=1809.4 J = 1.8094 KJ = 1.81 KJ
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