50g of oxygen at NTP is compressed adiabatically to a pressure of 5 atmosphere. The work done on the gas, if `gamma =1.4 and R = 8.31 J mol^(-1)K^(-1)` is

Options

A. `-5173 J`
B. `1131 J`
C. `-1364 J`
D. `5673 J`

Answer

A

Explanation

Here, `T_(1)=273 K, P_(1)=1 atm, P_(2)=5atm`
no of moles of oxygen `=(50)/(32)`
`rArr T+2=T_(1)(P_(1)/(P_(2)))^(gamma-1)/(gamma) = 3273((5)/(1))^(14-1)/(1.4)`
`=273xx(5)^(2//7)=273xx1.58=432.37`
`W=(nR)/(gamma-1)[(t_(1)-t_(2))]=(50)/(32)xx(8.31)/(1.4-1)(273-432.37)`
=-5173 J