A thermodynamic process is carried out from an original state D to an intermediate state E by the linear process shown in figure. The total work is done by the gas from D to E to F is

Options

A. 100 J
B. 800 J
C. 300 J
D. 250 J

Answer

B

Explanation

Total work done by the gas from D to E to F is equal to the area of `DeltaDEF`
`therefore` The area of `Delta DEF=(1)/(2)DFxxEF`
Here DF change in pressure =600-200=400 N `m^(-2)` Also EF=change in volume = `7m^(3)-3m^(3)=4m^(3)`
Area of `DeltaDEF =(1)/(2)xx400xx4=800J`
Thus the total work done by the gas from D to E to F is 800 J.