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A thermodynamical system undergoes cycli...

A thermodynamical system undergoes cyclic process ABCDA as shown in figure work done by the system is

A

zero

B

`2P_(0)V_(0)`

C

`P_(0)V_(0)`

D

`(3)/(2)P_(0)V_(0)`

Text Solution

Verified by Experts

The correct Answer is:
A
As is clear form figure
`W_(BCOB)`=-area of `DeltaCBO=(P_(0)V_(0))/(2)`
`W_(AODA)`=+area of `DeltaAOD=+(P_(0)V_(0))/(2)`
`therefore W_(net)=W_(BCOB)+W_(AODA)`
`=-(P_(0)V_(0))/(2)+(P_(0)V_(0))/(2)=zero`
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