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A carnot engine takes 900 Kcal of heat f...

A carnot engine takes 900 Kcal of heat from a reservoir at `723^(@)C ` and exhausts it to a sink at `30^@C` the work done by the engine is

A

`2.73xx10^(6) cal`

B

`3.73xx10^(6) cal`

C

`6.27xx10^(5) cal`

D

`3.73xx10^(5) cal`

Text Solution

Verified by Experts

The correct Answer is:
C
Here `Q_(1)=900 kcal =900xx10^(3) cal =9xx10^(5) cal`
`T_(1)=723^(@)C=723 + 273 =996 K`
`t_(2)=30^(@)C = 30 + 273 =303K`
`therefore (_(1))/(Q_(2))=(T_(1))/(T_(2))`
`therefore Q_(2)=(T_(2))/(T_(1))Q_(1)=(303)/(996)xx9xxx10^(5)=2.73xx10^(5) cal`
Now work done by the engine W=`Q_(1)-Q_(2)`
`=9x10^(5)-2.73xx10^(5)`
`(9-2.73)xx10^(5)=6.27xx10^(5) cal`
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