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Assetion : No engine can have efficiency...

Assetion : No engine can have efficiencyt greater than that of the carnot engine
Reason : The efficiencyt of a cornot engine is given by `eta =1-(T_(2))/(T_(1))`

A

If both assetion and reason are true and reaasons is the correct expanation of assetion

B

If both assetion and reason are tur but reason is not the correct explanation of assetion

C

If assertion is true but reason is false

D

If both assertion and reason are false.

Text Solution

Verified by Experts

The correct Answer is:
B
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The efficiency of a heat engine is defined as the ratio of the mechanical work done by the engine in one cycle to the heat absorbed from the high temperature source . eta = (W)/(Q_(1)) = (Q_(1) - Q_(2))/(Q_(1)) Cornot devised an ideal engine which is based on a reversible cycle of four operations in succession: isothermal expansion , adiabatic expansion. isothermal compression and adiabatic compression. For carnot cycle (Q_(1))/(T_(1)) = (Q_(2))/(T_(2)) . Thus eta = (Q_(1) - Q_(2))/(Q_(1)) = (T_(1) - T_(2))/(T_(1)) According to carnot theorem "No irreversible engine can have efficiency greater than carnot reversible engine working between same hot and cold reservoirs". Efficiency of a carnot's cycle change from (1)/(6) to (1)/(3) when source temperature is raised by 100K . The temperature of the sink is-

Carnot engine is an ideal heat engine, which converts heat energy into mechanical energy. Efficiency of Carnot engine is given by eta =1 - (T_2 // T_1) , where T_1 is temperature of source and T_1 , is temperature of sink. If Q_1 is the amount of heat absorbed/cycle from the source, Q_2 is the amount of heat rejected/cycle to the sink and W is the amount of useful work done/cycle, then W= Q_1 -Q_2 and (Q_2)/(Q_1) = (T_2)/(T_1) Work done/cycle by the engine in the above question is. if source and sink temperature respectively 227 and 127 . heat absorbed by engine is given 6 .

Carnot engine is an ideal heat engine, which converts heat energy into mechanical energy. Efficiency of Carnot engine is given by eta =1 - (T_2 // T_1) , where T_1 is temperature of source and T_1 , is temperature of sink. If Q_1 is the amount of heat absorbed/cycle from the source, Q_2 is the amount of heat rejected/cycle to the sink and W is the amount of useful work done/cycle, then W= Q_1 -Q_2 and (Q_2)/(Q_1) = (T_2)/(T_1) A Carnot engine absorbs 6 xx 10^5 " cal. at "227^@ C. Heat rejected to the sink at 127^@ C is

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