The charge on a parallel plate capacitor varies as `q = q_(0) "cos" 2 pit`. The plates are very large and close together (area = A, separation = d). The displacement current through the capacitor is

Options

A. `q_(0)2pi upsilon sin pi upsilont`
B. `-q_(0)2pi upsilon sin 2pi upsilont`
C. `q_(0)2pi sin pi upsilont`
D. `q_(0)pi upsilon sin2pi upsilont`

Answer

B

Explanation

Displacement current,
`I_(D)` : conduction current, `I_(C)`
`therefore" "(dq)/(dt)=(d)/(dt)[q_(0)cos 2piupsilont]=-q_(0)2piupsilon sin 2pi upsilont`