If a variable frequency ac source is connected to a capacitor then with decrease in frequency the displacement current will

Options

A. increase
B. decrease
C. remains constant
D. first decrease then increase

Answer

B

Explanation

Current through capacitor,
`I=(E)/(X_(C))=(E)/((1)/(omegaC))=omegaCE=2piupsilonCEor Ipropupsilon.`
`therefore` decrease in frequency `upsilon` of ac source decreases the conduction current. As displacement current is equal to conduction current, decrease in `upsilon` decreases displacement current in circuit.