Which among the following does not represent Maxwell's equation?

Options

A. `ointvecE.vec(dA)=(q)/(epsilon_(0))`
B. `ointvecB.vec(dA)=0`
C. `ointvecE.vec(dl)=(-dB)/(dt)`
D. `oint vecB.vec(dl)=mu_(0)I_(C)+mu_(0)epsilon_(0)(dphi_(E))/(dt)`

Explanation

To determine which option does not represent Maxwell's equations, we first need to understand the four fundamental equations that comprise Maxwell's equations. They are:

1. **Gauss's Law for Electricity**:
\[ \oint \mathbf{E} \cdot d\mathbf{A} = \frac{Q_{enc}}{\varepsilon_0} \]
This relates the electric field \(\mathbf{E}\) to the charge \(Q_{enc}\) enclosed in a surface.

2. **Gauss's Law for Magnetism**:
\[ \oint \mathbf{B} \cdot d\mathbf{A} = 0 \]
This states that there are no magnetic monopoles; the net magnetic flux through a closed surface is zero.

3. **Faraday's Law of Induction**:
\[ \oint \mathbf{E} \cdot d\mathbf{l} = -\frac{d\Phi_B}{dt} \]
This indicates that a changing magnetic field \(\Phi_B\) induces an electric field \(\mathbf{E}\).

4. **Ampère-Maxwell Law**:
\[ \oint \mathbf{B} \cdot d\mathbf{l} = \mu_0 I_{enc} + \mu_0 \varepsilon_0 \frac{d\Phi_E}{dt} \]
This law relates the magnetic field \(\mathbf{B}\) to the electric current \(I_{enc}\) and the changing electric field \(\Phi_E\).

Now, let's analyze the options provided in the question:

1. **Option 1**: Represents Gauss's Law for Electricity.
2. **Option 2**: Represents Gauss's Law for Magnetism.
3. **Option 3**: Represents Faraday's Law of Induction, but it is incorrectly stated as \(E \cdot dL = -D\Phi_I/Dt\) instead of the correct form.
4. **Option 4**: Represents the displacement current term in the Ampère-Maxwell Law.

From the analysis, it is clear that **Option 3** does not correctly represent Maxwell's equations because it misstates Faraday's Law.

### Final Answer:
**Option 3 does not represent Maxwell's equation correctly.**