If `mu_(0)` be the permeability and `epsilon_(0)` be the permittivity of a medium, then its refractive index is given by

Options

A. `(1)/(sqrt(mu_(0)epsilon_(0)))`
B. `(1)/(mu_(0)epsilon_(0))`
C. `sqrt(mu_(0)epsilon_(0))`
D. `mu_(0)epsilon_(0)`

Answer

C

Explanation

Refractive index of medium is `=(c)/(v)`
where `c=(1)/(sqrt(mu_(0)epsilon_(0)))and v=(1)/(sqrt(mu_(0)epsilon_(0)mu_(r)epsilon_(r)))`
`therefore" "mu=(1//sqrt(mu_(0)epsilon_(0)))/(1//sqrt(mu_(0)epsilon_(0)mu_(r)epsilon_(r)))=sqrt(mu_(r)epsilon_(r))`
Given `mu_(r)=mu_(0)` and `epsilon_(r)=epsilon_(0)` then `mu=sqrt(mu_(0)epsilon_(0))`