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The photon energy in units of eV for ele...

The photon energy in units of eV for electromagnetic waves of wavelength 2 cm is

A

`2.5xx10^(-19)`

B

`5.2xx10^(16)`

C

`3.2xx10^(-16)`

D

`6.2xx10^(-5)`

Text Solution

Verified by Experts

The correct Answer is:
D
As `E=(hc)/(lambda)=(6.6xx10^(-34)xx3xx10^(8))/(2xx10^(-2))=9.9xx10^(-24)J`
`=(9.9xx10^(-24))/(1.6xx10^(-19))eV=6.2xx10^(-5)eV`
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