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A linearly polarised electromagnetic wav...

A linearly polarised electromagnetic wave given as `E=E_(0)haticos(kz-omegat)` is incident normally on a perfectly reflecting wall `z=a`. Assuming that the material of the optically inactive, the reflected wave will be give as

A

`vec(E)_(r)=-E_(0)hat(i)cos(kx-omegat)`

B

`vec(E)_(r)=E_(0)hat(i)cos(kz+omegat)`

C

`vec(E)_(r)=-E_(0)hat(i)cos(kz+omegat)`

D

`vec(E)_(r)=E_(0) hat(i)sin(kz-omegat)`

Text Solution

Verified by Experts

The correct Answer is:
B
As the well is perfectly reflecting, there is no change in amplitude `E_(0)`.
Also the wall is optically inactive, so, there is no phase change.
After reflection, the wave travels along `-ve` z direction,
`therefore" "vecE_(r)=E_(0)hati cos (-kz-omegat)`
`=E_(0)haticos(kz+omegat)" "(because cos(-theta)=costheta)`
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