The shortest wavelength in the balmer series is `(R=1-097xx10^7m^-1)`

Options

A. 200 nm
B. 256.8 nm
C. 300 nm
D. 364.6 nm

Answer

D

Explanation

Wavelength for balmer series is
`(1)/(lambda)=R(1/(2^2)-1/(n^2))`
`n=prop`, the limit of the series observed.
`therefore (1)/(lambda)=R((1)/(4)-(1)/(prop^2))rArr(1)/(lambda)=(R)/(4)`or `lambda=(4)/(R)`.
Here, ryberg's constant `R=1.097xx10^7m^-1`
`therefore lambda=(4)/(1.097xx10^7)=364.6xx10^-9m=364.6nm`.