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in the question number 63, the frequency...

in the question number 63, the frequency of emitted photon due to the given transition is `(h=6.64xx10^(-34)Js,1eV=1.6xx10^(-19)J)`

A

`2.46xx10^(10)Hz`

B

`2.46xx10^(12)Hz`

C

`2.46xx10^(15)Hz`

D

`2.46xx10^(18)Hz`

Text Solution

Verified by Experts

The correct Answer is:
C
form bohr's third postulate of atomic theory the frequency of emitted photon
`hupsilon=E_2=-E_1=10.2eV therefore upsilon=(10.2)/(h)eV`
Here, `10.2eV=10.2xx1.6xx10^(-19)J,h=6.64xx10^(34)J_s`
`therefore upsilon=(10xx1.6xx10^(-19))/(6.64xx10^(-34))=2.46xx10^(15)Hz`.
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