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A difference of 2.3 eV separates two ene...

A difference of 2.3 eV separates two energy levels in an atom. What is the frequency of radiation emitted when the atom transits form the upper level to the lower level.

A

`2.6xx10^(13)Hz`

B

`2.6xx10^(14)Hz`

C

`2.6xx10^(18)Hz`

D

`2.6xx10^(18)Hz`

Text Solution

Verified by Experts

The correct Answer is:
B
Here, `E_(U)-E_(L)2.3eV=2.3xx1.6xx10^(-19)J` From third postulate of bohr's atomic model, `hupsilon=E_(U)-E_(L)`
or `upsilon=(E_U-E_L)/(h)=(2.3xx1.6xx10^(-19))/(6.64xx10^(-34))=5.6xx10^(14)Hz`.
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