The ground state energy of hydrogen atom is -13.6eV. What are P.E. and K.E. of electron in this state?

Options

A. `2.18xx10^(-14)J`
B. `2.18xx10^(-16)J`
C. `2.18xx10^(-18)J`
D. `2.18xx10^(-19)J`

Answer

C

Explanation

Here the ground state energy , (E) `=-13.6eV` since, K.E. of the electron `=-13.6eV`
`=13-6xx1.6xx10^(-19)J=21.76xx10^(-19)J=2.18xx10^(-18)J`.