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An electron is revolving in the n^(th) o...

An electron is revolving in the `n^(th)` orbit of radius `4.2 Å`, then the value of n is `(r-1=0.529 Å)`

A

4

B

5

C

6

D

3

Text Solution

Verified by Experts

The correct Answer is:
D
Since `r_npropn^(2),(r_n)/(r_1)=(n^2)/((1)^2)`
`therefore r_n=n^2r_1`or `n^2=(r_n)/(r_1)`
`rArrn=sqrt((r_n)/(r_1))=sqrt((4.2)/(0.529))=sqrt(7.939)=2.81approx3`.
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