A potential barrier of 0.3 V exists across a p-n junction. If the depletion region is 1 `mu`m wide, what is the intensity of electric field in this region?

Options

A. `2xx10^5 V m^(-1)`
B. `3xx10^5 V m^(-1)`
C. `4xx10^5 V m^(-1)`
D. `5xx10^5 V m^(-1)`

Explanation

To find the intensity of the electric field (E) in the depletion region of a p-n junction, we can use the formula:

\[ E = \frac{V}{D} \]

where:
- \( V \) is the potential barrier (in volts),
- \( D \) is the width of the depletion region (in meters).

### Step-by-Step Solution:

1. **Identify the given values:**
- Potential barrier, \( V = 0.3 \, \text{V} \)
- Width of the depletion region, \( D = 1 \, \mu m = 1 \times 10^{-6} \, \text{m} \)

2. **Substitute the values into the formula:**
\[ E = \frac{0.3 \, \text{V}}{1 \times 10^{-6} \, \text{m}} \]

3. **Calculate the electric field:**
\[ E = \frac{0.3}{1 \times 10^{-6}} = 0.3 \times 10^6 \, \text{V/m} \]

4. **Convert the result to standard form:**
\[ E = 3 \times 10^{5} \, \text{V/m} \]

### Final Answer:
The intensity of the electric field in the depletion region is \( 3 \times 10^{5} \, \text{V/m} \).

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