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In a full wave junction diode rectifier,...

In a full wave junction diode rectifier, the input a.c. has r.m.s. value of 20 V. The transformer used is a step up transformer having primary and secondary turns ratio 1: 2. Calculate the d.c. voltage in the rectified output.

A

12 V

B

24 V

C

36 V

D

42 V

Text Solution

Verified by Experts

The correct Answer is:
C
Here, input `V_(rms)=20 V`
Peak value of input voltage
`V_0=sqrt2 V_(rms)=sqrt2 xx 20 =28.28 V`
Since the transformer is a step up transformer having transformer ratio 1 : 2, the maximum value of output voltage of the transformer applied to the diode will be
`V'_0=2xxV_0=2xx28.28 V`
`therefore` dc voltage =`(2V_0')/pi=(2xx2xx28.28)/(22//7)=36 V`
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